There are a lot of things which could be cut — trees, paper, “the rope”. In this problem you are going to cut a sequence of integers.
There is a sequence of integers, which contains the equal number of even and odd numbers. Given a limited budget, you need to make maximum possible number of cuts such that each resulting segment will have the same number of odd and even integers.
Cuts separate a sequence to continuous (contiguous) segments. You may think about each cut as a break between two adjacent elements in a sequence. So after cutting each element belongs to exactly one segment. Say, [4,1,2,3,4,5,4,4,5,5][4,1,2,3,4,5,4,4,5,5] →→ two cuts →→[4,1|2,3,4,5|4,4,5,5][4,1|2,3,4,5|4,4,5,5]. On each segment the number of even elements should be equal to the number of odd elements.
The cost of the cut between xx and yy numbers is |x−y|bitcoins. Find the maximum possible number of cuts that can be made while spending no more than Bbitcoins.
继续阅读Codeforces round 493 div2 B.Cutting